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Question

A dog at point A goes in pursuit of a fox 40 m away. The dog takes a leap of 2 m against 1 m long leap of the fox. If the dog makes two leaps to the fox's three at what distance from A will the dog catch up with the fox ?

A
150 m
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B
160 m
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C
105 m
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D
120 m
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Solution

The correct option is A 160 m
Distance per leap of dog =2m
Distance per leap of fox=1m
Dog takes 2 leaps and fox takes 3 leaps in the same time
Distance covered by dog in 2 leaps =2×2=4m
Distance covered by fox in 3 leaps =1×3=3m
In two leaps of dog distance reduces by =4m3m=1m
No of leaps required by dog to cover the gap of 40 m =40×2=80
Distance covered by dog in 80 leaps =2×80=160m
Hence the dog will catch up with the fox at 160 m from A.

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