A door 1.6m wide requires a minimum force of 1N to be applied at the free end to open or close it. The minimum force that is required at a point 0.4m away from the hinges for opening or closing the door is
A
1.2N
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B
2.4N
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C
3.6N
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D
4N
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Solution
The correct option is D4N We know that, torque τ=F×d
From the question, τ=1×1.6=1.6Nm
So, when d1=0.4m τ=F1×d1
or F1=τd1=1.60.4=4N