CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A double homozygous tall pea plant with green cotyledons is crossed with pure dwarf plant with yellow cotyledons. The offspring are crossed with pure dwarf plant with green cotyledons. How many different phenotypes will be obtained in this progeny?

A
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4
TtYy
ttyy
TY Ty tY ty
ty TtYy
(tall and yellow cotyledon)
Ttyy
(tall and greencotyledon)
ttYy
(dwarf and yellow cotyledon)
ttyy
(dwarf and green cotyledon)
  1. Tallness and yellow cotyledons are dominant in pea plants over dwarf and green ones. A cross between double homozygous tall pea plant with green cotyledons (TTyy) and pure dwarf plant with yellow cotyledons (ttYY) will give all tall progeny with yellow cotyledon (TtYy). Cross of tall plant with yellow cotyledon (TtYy) with pure dwarf plant with green cotyledons (ttyy) gives four phenotypes. Correct answer is C.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Law of Dominance
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon