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Question

An agricultural scientist crossed pure-breed round and yellow cotyledon pea plant with wrinkled and green cotyledon pea plant. He observed 800 plants that are heterozygous dominant for both characters. Compute the total number of plants obtained in F2generation.

A
1000
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B
800
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C
1600
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D
3200
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Solution

The correct option is D 3200
In the progeny of a dihybrid cross, the proportion of plants with heterozygous dominant genotype for both the characters is 4 out of 16.
1 RRYY: 2 RRYy: 1 RRyy: 2 RrYY: 4 RrYy: 2 Rryy: 1 rrYY: 2 rrYy: 1 rryy.
In the cross given, the number of dominant heterozygotes for both the traits = 800
Therefore, the total number of plants in F2 generation = 800 × (16/4)
= 3200

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