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Question

(a) Draw the molecular structures of the following compounds:
(i) N2O5
(ii) XeOF4
(b) Explain the following observations
(i) Sulphur has a greater tendency for catenation than oxygen.
(ii) ICl is more reactive than I2.
(iii) Despite lower value of its electron gain enthalpy with negative sign, fluorine (F2) is a stronger oxidizing agent than Cl2.

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Solution


(b) (i) Due so strong S-S bond and less interelectronic repulsion, sulphur has greater tendency for catenation.
(ii) I-CI bond is polar and hence, more reactive compound to I2 in which II bond is non-polar.
(iii) Due to high electronegativity and small size of fluorine, it acts as stronger oxidizing agent.

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