A drawing pin is pushed against a wooden table with a force of $10 N$ . The pressure exerted by the pin at a point on the table, if an area of the point is $0.01 {c m}^{2}$ is $10^{x}$ pa. Find x?

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Solution

Force = 10N Area = 0.01 ${c m}^{2}$
Pressure = $\frac{F o r c e}{A r e a} = \frac{10 N}{10^{- 2} {c m}^{2}}$
Pressure = $10^{7} P a o r N / m^{2}$

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A drawing pin is pushed against a wooden table with a force of 10N. The pressure exerted by the pin at a point on the table, if an area of the point is 0.01cm2 is 10xpa. Find x?

Force = 10N Area = 0.01cm2Pressure = ForceArea=10N10−2cm2 Pressure = 107Pa orN/m2

A drawing pin is pushed against a wooden table with a force of $10 N$ . The pressure exerted by the pin at a point on the table, if an area of the point is $0.01 {c m}^{2}$ is $10^{x}$ pa. Find x?

Force = 10N Area = 0.01 ${c m}^{2}$
Pressure = $\frac{F o r c e}{A r e a} = \frac{10 N}{10^{- 2} {c m}^{2}}$
Pressure = $10^{7} P a o r N / m^{2}$