Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:

• A. 21s
• B. 29s
• C. 31s
• D. 37s

Answer 1

The correct option is B

29s

Step 1: Given:

1. The drunkard walks along a straight road.
2. He takes 5 steps forward and 3 steps backward
3. Each step is 1 m long and takes 1 s
4. There is a pit on the road 11 m away from the starting point

Step 2: Time after which he will fall into the pit

He takes 5 steps forward and 3 steps backward in 8 seconds,

Leaving him 2 meters from his starting location,
$x=5-3=2min8sec.$

Now,

He will be 6 meters distant from his starting place after 24 seconds.

He walks 5 meters forward before falling into a pit 11 meters away from where he started.

$TotaltimeT=24+5=29sec.$

Therefore, the drunkard will fall into the pit after 29 seconds.

Hence, the correct option is B.