A drunkard is walking along a straight road.He takes 5 steps forward and 3steps backward followed again by 5 step forward and 3step backward and so on.Each step is 1m and takes 1s .There is a pit on the road 11m away from starting point.The drunkard will fall into the pit after.....ANS:29s(pls give explanation becoz I have already gone through the solution but not able to follow some steps especially why they calculate the time for 6m)

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Solution

For 8 total steps it takes 8 seconds,
and moves in total 2 steps forward (2 m)

Therfore,

3*2 m = 6 m

At 3rd cycle Time Elapsed 24 s

After walking 5 m forward, he takes 5 s more.

It becomes 11 m.

Time = 24 + 5 = 29sec

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For 8 total steps it takes 8 seconds, and moves in total 2 steps forward (2 m) Therfore, 3*2 m = 6 m At 3rd cycle Time Elapsed 24 s After walking 5 m forward, he takes 5 s more. It becomes 11 m. Time = 24 + 5 = 29sec

For 8 total steps it takes 8 seconds,
and moves in total 2 steps forward (2 m)

Therfore,

3*2 m = 6 m

At 3rd cycle Time Elapsed 24 s

After walking 5 m forward, he takes 5 s more.

It becomes 11 m.

Time = 24 + 5 = 29sec