Question

(a) During each cycle, a Carnot engine absorbs 750 J as heat from a high-temperature reservoir at 360K, with the low-temperature reservoir at $280K.$ How much work is done per cycle?(b) The engine is then made to work in reverse to function as a Carnot refrigerator between those same two reservoirs. During each cycle, how much work is required to remove $1200J$ as heat from the low-temperature reservoir?

Answer 1

(a) Carnot efficiency $=1-T_L/T_H$.

This gives 0.222 in this case.

Using this value

$W=\left(0.222\right)\left(750J\right)=167J$

(b) Now, $K_C=3.5.$ Then, $|W|=1200/3.5=343J$