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Question

A(t2,2t),B(1t2,2t)ands(1,0),then1SA+1SBisequalto

A
2
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B
12
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C
15
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D
1
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Solution

The correct option is D 1
A=(t2,2t)

B=(1t2,2t)

S=(1,0)

Distance formula=(x2x1)2+(y2y1)2

SA=(t21)2+(2t0)2

=t4+12t2+4t2

=t4+1+2t2

=(t2+1)2

SA=t2+1

SB=(1t21)2+(2t0)2

=1t4+12t2+4t2

=1t4+1+2t2

=(1t2+1)2

=1t2+1

SB=1+t2t2

Now 1SA+1SB

=1t2+1+t21+t2=1+t21+t2=1.

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