(a) Explain the following in terms of gain or loss of oxygen with one example each:
(i) oxidation (ii) reduction
(b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction. Name (i) substance oxidised, and (ii) substance reduced.

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Solution

(a) (i) Oxidation is the gain of oxygen.

Example:
2Mg + O₂→ 2MgO
Here, Mg is oxidised to MgO by accepting oxygen.

(ii) Reduction is the loss of oxygen.

Example:
ZnO + C → Zn + CO
Here, ZnO is reduced to Zn by losing oxygen.

(b) Balanced chemical reaction is as follows:
2Cu + O₂→ 2CuO

(i) The substance oxidised is copper.
(ii) The substance reduced is oxygen.

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(a) Explain the following in terms of gain or loss of oxygen with one example each: (i) oxidation (ii) reduction (b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction. Name (i) substance oxidised, and (ii) substance reduced.

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(i) oxidation (ii) reduction
(b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction. Name (i) substance oxidised, and (ii) substance reduced.