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Question

A factory production line is manufacturing bolts using three machines, A, B and C. Of the total output, machine A is responsible for 25%, machine B for 35% and machine C for the rest. It is known from previous experience with the machines that 5% of the output from machine A is defective, 4% from machine B and 2% from machine C. A bolt is chosen at random from the production line and found to be defective. What is the probability that it came from (a) machine A

A
0.632
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B
0.362
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C
0.487
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D
none of these
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Solution

The correct option is B 0.362
Let
A be bolt manufactured from machine A
B be bolt manufactured from machine B
C be bolt manufactured from machine C
D be bolt is defective
Given:
P(A)=25%=0.25,P(B)=35%=0.35,P(C)=40%=0.4
P(D/A)=5%=0.05,P(D/B)=4%=0.04,P(D/C)=2%=0.02
To find:
The probability that the bolt is manufactured by machine A if it is defective.
i.e., P(A/D)=P(A).P(D/A)P(A).P(D/A)+P(B).P(D/B)+P(C).P(D/C)=0.25×0.050.25×0.05+0.35×0.04+0.4×0.02=0.01250.0345P(A/D)=0.362

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