Question

A fair coin is tossed four times. The probability that heads exceed tails in number is

• A. $\frac{5}{16}$
• B. $\frac{6}{16}$
• C. $\frac{7}{16}$
• D. $\frac{8}{16}$

Answer 1

The correct option is A $\frac{5}{16}$

A coin is tossed four times: $n\left(S\right)=2^4=16$
Cases when heads exceed tails: $HHHH,HHHT,HHTH,HTHH,THHH$ $=5$ cases
Probability that heads exceed tails in number is $=\frac{5}{16}$