Question

A fair coins is tossed independently four times. the probability of the event "the number of times heads show up is more than the number of times tails show up" is

• A. $\frac{1}{16}$
• B. $\frac{1}{8}$
• C. $\frac{1}{4}$
• D. $\frac{5}{16}$

Answer 1

The correct option is D $\frac{5}{16}$

n(s) = 16
favourable cases = {HHHT, HHTH, HTHH, THHH, HHHH}

no of favourable cases = 5

Required Probability $=\frac{5}{16}$