A fair die is thrown once. The probability of getting a composite number is

(a) $\frac{1}{3}$
(b) $\frac{1}{6}$
(c) $\frac{2}{3}$
(d) 0

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Solution

(a) $\frac{1}{3}$
In a single throw of a die, the possible outcomes are
1 , 2, 3, 4, 5 and 6
The total number of possible outcomes = 6
Let E be the event of getting a composite number.
Then, the favourable outcomes are 4 and 6.
Number of favourable outcomes = 2
∴ P(getting a composite number) = P(E) = $\frac{2}{6} = \frac{1}{3}$

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