Question

A father is $30years$ older than his son. In $12years$, the man will be three times as old as his son. Find their present ages.

Answer 1

Let the present age of the son be $x$ years

Then father's age will be $(x+30)$ years

Given after 12 years father will be three times as old as his son

Therefore,

$(x+12)3=x+30+12$

$3x+36=x+42$

$3x-x=42-36$

$2x=6$

$x=3$

$x+30=3+30=33$

So, the present age of son is 3 years and present age of the father is 33 years