A father is three times as old as his son. $5$ years ago, the father was four times as old as his son. After $5$ years, father's age will be

30

years more than the son's age

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25

years more than the son's age

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32

years more than the son's age

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three times the son's age

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Solution

The correct option is C $30$ years more than the son's age
Let the son's age be $x$ .
Father's age $= 3 x$
$∴ 3 x - 5 = 4 (x - 5)$
or $3 x - 5 = 4 x - 20$
or $20 - 5 = 4 x - 3 x$ or $x = 15$
After 5 years, son's age is $x + 5 = 15 + 5 = 20$ .
Father's age is $3 x + 5 = 45 + 5 = 50$ which is 30 years more than son's age.

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A father is three times as old as his son. 5 years ago, the father was four times as old as his son. After 5 years, father's age will be

The correct option is C 30 years more than the son's ageLet the son's age be x.Father's age =3x∴3x−5=4(x−5)or 3x−5=4x−20or 20−5=4x−3x or x=15After 5 years, son's age is x+5=15+5=20.Father's age is 3x+5=45+5=50 which is 30 years more than son's age.

A father is three times as old as his son. $5$ years ago, the father was four times as old as his son. After $5$ years, father's age will be