Question

The father's age 10 year ago was 35 years more than twice his son's age. After how many year from now will the father be twice his son's age?

• A. 15
• B. 20
• C. 25
• D. cannot be determine

Answer 1

The correct option is A 15

Let the son's age be $x$

Then according to given data

Father's age $y=3x+35------\left(1\right)$

Present age of father $=y+10$

Present age of son $=x+10$

After $t$ numbers of years, father be twice his son's age.

$y+10+t=2(x+10+t)$

On simplifying, $t=y-2x-10$

By $\left(i\right)t=35-10=25$

After $25$ years father will be twice his son's age