Question

A fertilizer contains phosporus as one of its constituents as shown below.

The percentage of phosporus required per kg of the fertilizer is .

• A. 20
• B. 50
• C. 100

Answer 1

The correct option is A 20

From the given graph, let us consider the points (1,0.2) and (3,0.6)

$\therefore \text{Slope}=\frac{\text{Rise}}{\text{Run}}$
$=\frac{0.6-0.2}{3-1}=\frac{0.4}{2}=0.2$

Therefore, every 1 kg of fertilizer contains 0.2 kg of phosporus.

Percentage of phosporus
= $\frac{0.2}{1}\times 100$
= 20%