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Question

Calculate the percentage of phosphorus in the fertilizer superphosphate, Ca(H2PO4)2 (correct to 1 decimal place.) [Ca = 40, H = 1, P = 31, O = 16]

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Solution

Molecular mass of fertiliser superphosphate, Ca(H2PO4)2 = 40 + 2(2 + 31 + 64) = 234 g
Mass of phosphorus in 234 g of fertiliser = 2(31) g = 62 g

Percentage of phosphorus=Mass of phosphorus in compoundMolecular mass of the compound×100Percentage of phosphorus=62234×100=26.5%


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