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Question

# (i) Calculate the percentage of phosphorus in the fertilizer superphosphate Ca(H2PO4)2. (H = 1; O = 16; P = 31; Ca = 40) (ii) Write out and balance the following equation correctly: Ca3(PO4)2 + H2SO4 $\stackrel{}{\to }$ Ca(H2PO4)2 + CaSO4 (iii) Copy and complete the following sentence: Superphosphate is an example of a compound called___________(acid salt / basic salt / normal salt).

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Solution

## (i) Molar mass of Ca(H2PO4)2 = (40 + (2 + 31 + 64)$×$2) g = 234 g mol-1 Amount of phosphorous in 234 g of superphosphate = (31$×$2) g = 62 g Percentage of phosphorus in superphosphate = $\left(\frac{62}{234}\right)×100=26.5%$ (ii) Balanced equation of the above reaction is: Ca3(PO4)2 + 2H2SO4 → Ca(H2PO4)2 + 2CaSO4 (iii) Superphosphate is an example of a compound called acid salt.

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