A fielder on the ground throws a ball at an angle of 15∘ to the horizontal with velocity VA at the wicket to dismiss the batsman. Had he thrown the ball at 45∘, with a speed VB to hit the wicket, then VBVAis
A
1√3
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B
√2
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C
√3
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D
1√2
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Solution
The correct option is D√2 To dismiss the batman the fielder has to make sure that the ball hits the wicket, so in both the cases the range of the ball needs to be the same.
Let RA be the range when ball is thrown with velocity VA at 15o
Let RB be the range when ball is thrown with velocity VB at 45o
⟹RA=RB
We know that for a ball thrown with velocity u at an angle θ, the range, R is given by,