Time of Flight
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T=5 s, H=31.25 m
T=5 s, H=45.6 m
T=11 s, H=31.25 m
T=10 s, H=45.1 m
- t1t2∝1R2
- t1t2∝R2
- t1t2∝R
- t1t2∝1R
- tan−1(34)
- tan−1(43)
- Not obtainable from the given data
- sin−1(34)
A body is thrown with a velocity of 9.8 m/s making an angle of 30∘ with the horizontal. It will hit the ground after a time
1.5 s
1 s
3 s
2 s
- 98.0 m/s
- 24.5 m/s
- 49.0 m/s
- 73.5 m/s
A projectile can have the same range R for two angles of projection. If T1 and T2 be the time of flights in the two cases, then the product of the two time of flights is directly proportional to
- R2
R
(1/R)
1/R2
A ball thrown by a boy is caught by another after 2 sec. some distance away in the same level. If the angle of projection is 30∘, the velocity of projection is
None of these
19.6 m/s
9.8 m/s
14.7 m/s
- 5 sec
- 0.625 sec
- 2.5 sec
- 1.25 sec
If for a given angle of projection, the horizontal range is doubled, the time of flight becomes
The friction of the air causes vertical retardation equal to one tenth of the acceleration due to gravity (Take g = 10ms−2). The time of flight will be decreased by