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Question

A particle is thrown with velocity u at an angle α from the horizontal. Another particle is thrown with the same velocity at an angle α from the vertical. The ratio of times of flight of two particles will be

A

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B

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C

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D

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Solution

The correct option is C For first particles angle of projection from the horizontal is a. So T1=2u sin αg For second particle angle of projection from the vertical is α. it mean from the horizontal is 90−α ∴ T2=2u sin(90−α)g=2u cos αg. So ratio of time of flight T1T2=tan α.

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