Question

Referring to above question, the angle with the horizontal at which the projectile was projected is

- tan−1(34)
- tan−1(43)
- Not obtainable from the given data
- sin−1(34)

Solution

The correct option is **B** tan−1(43)

The angle of projection is given by θ=tan−1(vyvx)=tan−1(43)

The angle of projection is given by θ=tan−1(vyvx)=tan−1(43)

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