A film show lasted for 31-3 hours- Out of this time- 13-4 hours was spent on advertisements- What was the actual duration of the film-

Given #160; #160;Total show time of film = 31/3 hours #160; =10/3 #160; hoursadds time consumption = 13/4hours #160; = 7/4 hoursactual ti ...

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Standard VII

Mathematics

Multiplication of Fractions

A film show l...

Question

A film show lasted for $3 \frac{1}{3}$ hours. Out of this time, $1 \frac{3}{4}$ hours was spent on advertisements. What was the actual duration of the film?

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Solution

Given Total show time of film $= 3 \frac{1}{3} h o u r s = \frac{10}{3}$ hours
adds time consumption $= 1 \frac{3}{4} h o u r s = \frac{7}{4}$ hours
actual time of film $= \frac{10}{3} - \frac{7}{4} = \frac{40 - 21}{12} = \frac{19}{12}$
actual time $= 1 \frac{7}{12}$ hours.

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A film show lasted for 313 hours. Out of this time, 134 hours was spent on advertisements. What was the actual duration of the film?

Given Total show time of film =313hours=103 hoursadds time consumption =134hours=74 hoursactual time of film =103−74=40−2112=1912actual time =1712 hours.

A film show lasted for $3 \frac{1}{3}$ hours. Out of this time, $1 \frac{3}{4}$ hours was spent on advertisements. What was the actual duration of the film?

Given Total show time of film $= 3 \frac{1}{3} h o u r s = \frac{10}{3}$ hours
adds time consumption $= 1 \frac{3}{4} h o u r s = \frac{7}{4}$ hours
actual time of film $= \frac{10}{3} - \frac{7}{4} = \frac{40 - 21}{12} = \frac{19}{12}$
actual time $= 1 \frac{7}{12}$ hours.