Question

Question 4(a)

Find the product using suitable properties:

$738\times 103$

Answer 1

$738\times 103$

103 can be split as (100 + 3) as calculations with 100 makes it easier and faster.

$738\times 103=738\times (100+3)$

Now using the distributive property,

a×(b+c) = (a×b) + (a×c)

we can take 738 as common,

= $(738\times 100)+(738\times 3)$

= $73800+2214$

= $73800+2214$

= $76014$