A Fischer projection of (2R, 3S)-2,3-butanediol is:

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Solution

The correct option is A
Cases of R and S nomenclature
If the 4th (least) priority group is on the vertical position then clockwise direction from priority order 1 to 3 will be R.
If the 4th (least) priority group is on the vertical position then anti-clockwise direction from priority order 1 to 3 will be S.
If the 4th (least) priority group is on the horizontal position then clockwise direction from priority order 3 to 1 will be R.
If the 4th (least) priority group is on the horizontal position then anti-clockwise direction from priority order 3 to 1 will be S.
The R/S nomenclature of all the four given structure is given by
Hence correct fischer projection of (2R, 3S)-2,3-butanediol is option a.
$\Rightarrow$ The compound is optically inactive even though it has 2 chiral carbons because of 2R and 3S.

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Similar questions

It is given that when (±)-2,3-dibromobutane reacts with $K O H$ , some of the products formed are:

Explain via mechanism and then choose the correct ones from the following.

Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.
Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a single major product.
Monosubstitution of (2R,3R)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.
Monosubstitution of (2S,3S)-2,3-dibromobutane using $O H^{-}$ yields a mixture of products.

90^{0}

(2 r - 3 s) (2 r + 3 s) + (3 s - 4 q) (3 s + 4 q) + (4 q - 2 r) (4 q + 2 r) = 0

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