A fish is swimming in a river at a depth of 20 cm from the surface of the water. Refractive Index of water is 4/3. The depth at which an eagle flying above the water sees the fish is
In the given situation,
Refractive Index of water = Real depthApparent depth
Refractive index of water, μwater = 1(34) = 43
Therefore, Apparent depth = 20×34 = 15 cm