A fish is swimming in a river at a depth of 20 cm from the surface of the water. Refractive Index of water is 43. At what depth will an eagle flying above the water and exactly above the fish will see the fish?
15 cm
Given:
Refractive index of water, μwater = 43
Real depth of fish from surface of water =20 cm
In the given situation,
Refractive Index of water =μwater=Real depthApparent depth
⇒Apparent depth=Real depthμwater
⇒Apparent depth=2043
Therefore, Apparent depth=20×34 = 15 cm. The eagle will perceive the fish to be at 15 cm depth from the water surface.