A fish tank is in the form of a cuboid- external measure of that cuboid are 80 cm - 40 cm - 30 cm- The base- side faces and back face are to be coveredwith a coloured paper- Find the area of the paper needed-

Given: Length, l = 80 cm Breadth, b = 40 cm Height, h = 30 cm Area of the base of the tank = lb = 80 times; 40 = 3200 cm2 Area of side faces = 2bh = 2 tim ...

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Mathematics

Total Surface Area of a Cuboid

A fish tank i...

Question

A fish tank is in the form of a cuboid, external measure of that cuboid are 80 cm $\times$ 40 cm $\times$ 30 cm. The base, side faces and back face are to be covered with a coloured paper. Find the area of the paper needed.

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Solution

Given:
Length, l = 80 cm
Breadth, b = 40 cm
Height, h = 30 cm
Area of the base of the tank = lb
= 80 × 40
= 3200 cm²
Area of side faces = 2bh
= 2 × 40 × 30
= 2400 cm²
And,
Area of the back face = hl
= 30 × 80
= 2400 cm²
Thus, we have:
Area of the paper needed = 3200 + 2400 + 2400 = 8000 cm²

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A fish tank is in the form of a cuboid, external measure of that cuboid are 80 cm × 40 cm × 30 cm. The base, side faces and back face are to be covered with a coloured paper. Find the area of the paper needed.

Given: Length, l = 80 cm Breadth, b = 40 cm Height, h = 30 cm Area of the base of the tank = lb = 80 × 40 = 3200 cm2 Area of side faces = 2bh = 2 × 40 × 30 = 2400 cm2 And, Area of the back face = hl = 30 × 80 = 2400 cm2 Thus, we have: Area of the paper needed = 3200 + 2400 + 2400 = 8000 cm2

A fish tank is in the form of a cuboid, external measure of that cuboid are 80 cm $\times$ 40 cm $\times$ 30 cm. The base, side faces and back face are to be covered with a coloured paper. Find the area of the paper needed.

Given:
Length, l = 80 cm
Breadth, b = 40 cm
Height, h = 30 cm
Area of the base of the tank = lb
= 80 × 40
= 3200 cm²
Area of side faces = 2bh
= 2 × 40 × 30
= 2400 cm²
And,
Area of the back face = hl
= 30 × 80
= 2400 cm²
Thus, we have:
Area of the paper needed = 3200 + 2400 + 2400 = 8000 cm²