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Byju's Answer

Standard XI

Physics

Buoyant Force

A fisherman h...

Question

A fisherman hooks an old log of wood of weight 12N and volume 1000 $c m^{3}$ . He pulls the log half way out of water. The tension in the string at this instant is

12 N

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8 N

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10 N

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7 N

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Solution

The correct option is D
7 N

Forces acting on log will be,

mg downwards

and buoyant force,

$(V_{i m}) ρ_{l i q u i d} g = (\frac{V}{2}) ρ_{w a t e r} g u p w a r d s .$

Tension in string is,

$T = M g - (\frac{V}{2}) ρ_{w a t e r} g = 7 N$

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A fisherman hooks an old log of wood of weight 12N and volume 1000 $c m^{3}$ . He pulls the log half way out of water. The tension in the string at this instant is

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Q. A string is wrapped round a log of wood and it is pulled witha force

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I Tension

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II Tension

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A fisherman hooks an old log of wood of weight 12N and volume 1000 cm3. He pulls the log half way out of water. The tension in the string at this instant is

The correct option is D 7 N Forces acting on log will be, mg downwards and buoyant force, (Vim)ρliquid g=(V2)ρwater g upwards. Tension in string is, T=Mg−(V2)ρwater g=7N

A fisherman hooks an old log of wood of weight 12N and volume 1000 $c m^{3}$ . He pulls the log half way out of water. The tension in the string at this instant is

The correct option is D
7 N

Forces acting on log will be,

mg downwards

and buoyant force,

$(V_{i m}) ρ_{l i q u i d} g = (\frac{V}{2}) ρ_{w a t e r} g u p w a r d s .$

Tension in string is,

$T = M g - (\frac{V}{2}) ρ_{w a t e r} g = 7 N$