Question

A fixed beam ABC fixed at the ends $A$ and $C$ is loaded as shown in figure. El is constant for whole beam.
The final end moment at support C.is kNm

• A. 10

Answer 1

The correct option is A 10
$M_{FAB}=\frac{60}{4}=15kNm=M_{FBA}$
$M_{FBC}=\frac{-15\times 3^2}{12}=-11.25kNm$
$M_{FCB}=+11.25kNm$
$\begin{array}{ccccc}\text{Joint}& \text{Member}& \text{Stiffness}& \Sigma k& \Delta F\\ & BA& 4EI/6& & 1/3\\ B& & & \frac{12EI}{6}& \\ & BC& 4EI/3& & 2/3\end{array}$
Moment distribution method