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Block and Tackle System

A fixed pulle...

Question

A fixed pulley is driven by a $100 k g$ mass falling at a rate of $8.0 m$ in $4.0 s$ . It lifts a load of $75.0 k g f$ . What is the power input to the pulley taking the force of gravity on $1 k g$ as $10 N$ ?

200 W

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2000 W

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1000 W

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1050 W

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Solution

The correct option is B $2000 W$
As we know that $p o w e r (P) = f o r c e \times v e l o c i t y$

hence, $v e l o c i t y (v) = \frac{8}{4} = 2 m / s e c$

also tension force in the pulley $= 100 \times 10 n e w t o n$

hence $p o w e r (P) = 100 \times 10 \times 2 = 2000 w a t t$

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A fixed pulley is driven by a 100kg mass falling at a rate of 8.0m in 4.0s. It lifts a load of 75.0kgf. What is the power input to the pulley taking the force of gravity on 1kg as 10N ?

The correct option is B 2000WAs we know that power(P)=force×velocityhence, velocity(v)=84=2m/secalso tension force in the pulley=100×10newtonhence power(P)=100×10×2=2000watt

A fixed pulley is driven by a $100 k g$ mass falling at a rate of $8.0 m$ in $4.0 s$ . It lifts a load of $75.0 k g f$ . What is the power input to the pulley taking the force of gravity on $1 k g$ as $10 N$ ?

The correct option is B $2000 W$
As we know that $p o w e r (P) = f o r c e \times v e l o c i t y$

hence, $v e l o c i t y (v) = \frac{8}{4} = 2 m / s e c$

also tension force in the pulley $= 100 \times 10 n e w t o n$

hence $p o w e r (P) = 100 \times 10 \times 2 = 2000 w a t t$