Question

A floor measuring 15 m$\times$8 m is to be laid with tiles measuring 50 cm by 25 cm. Find the number of tiles required.

Answer 1

Length of floor $=15m=1500cm$

Breadth of floor $=8m=800cm$

Area of floor = $1500\times 800=1200000$ $c{m}^2$

Area of $1$ tile = $50\times 25=1250$ $c{m}^2$

Therefore,

Number of tiles required = $\frac{1200000}{1250}=960$ $tiles$