A floor which measures 15m x 8m is to be laid with tiles measuring 50 cm x 25cm. Find the number of tiles required.

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Solution

Area of floor = $1500 \times 800 = 1200000 c m^{2}$
Area of 1 tile = $50 \times 25 = 1250 c m^{2}$
Therefore,
Number of tiles required = $\frac{1200000}{1250} = 960 t i l e s$

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A floor which measures 15m x 8m is to be laid with tiles measuring 50 cm x 25cm. Find the number of tiles required.

Area of floor = 1500×800=1200000 cm2Area of 1 tile = 50×25=1250 cm2Therefore,Number of tiles required = 12000001250=960 tiles

Area of floor = $1500 \times 800 = 1200000 c m^{2}$
Area of 1 tile = $50 \times 25 = 1250 c m^{2}$
Therefore,
Number of tiles required = $\frac{1200000}{1250} = 960 t i l e s$