A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. The number such tiles required to cover a floor of area 1080 $m^{2}$ is

34000

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44000

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45000

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54000

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Solution

The correct option is C
45000

Area of parallelogram = Base $\times$ Height = 24 cm $\times$ 10 cm = 240 sq.cm.
Required number of tiles $= \frac{A r e a o f f l o o r}{A r e a o f 1 t i l e}$

$= \frac{1080 \times 100 \times 100}{240}$

(converting sq. m to sq. cm)

= 45000 tiles

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A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. The number such tiles required to cover a floor of area 1080 m2 is

The correct option is C 45000 Area of parallelogram = Base × Height = 24 cm × 10 cm = 240 sq.cm. Required number of tiles =Area of floorArea of 1 tile =1080×100×100240 (converting sq. m to sq. cm) = 45000 tiles

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. The number such tiles required to cover a floor of area 1080 $m^{2}$ is

The correct option is C
45000

Area of parallelogram = Base $\times$ Height = 24 cm $\times$ 10 cm = 240 sq.cm.
Required number of tiles $= \frac{A r e a o f f l o o r}{A r e a o f 1 t i l e}$

$= \frac{1080 \times 100 \times 100}{240}$

(converting sq. m to sq. cm)

= 45000 tiles