A flooring tile has the shape of a parallelogram whose base is $24$ cm and the corresponding height is $10$ cm. How many such tiles are required to cover a floor of area $1080 m^{2}$ ? (If required you can split the tiles in whatever way you want to fill up the corners).

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Solution

$\begin{matrix} A r e a o f t i l e = b a s e \times h e i g h t = 4 \times 10 = 4 c m^{2} A s s u m e, t o t a l n u m b e r o f t i l e s r e q u i r e d t o c o v e r a f l o o r o f a r e a 1080 m^{2} = n \to F o r o n l y o n e t i l e r e q u i r e d 4 c m^{2}, s o t o t a l r e q u i r e d 4 \times n = 1080 n = 270 \end{matrix}$

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A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10cm. How many such tiles are required to cover a floor of area 1080m2? (If required you can split the tiles in whatever way you want to fill up the corners).

Areaoftile=base×height=4×10 =4cm2Assume,totalnumberoftilesrequiredtocoverafloorofarea1080m2=n→Foronlyonetilerequired4cm2,sototalrequired4×n=1080n=270

A flooring tile has the shape of a parallelogram whose base is $24$ cm and the corresponding height is $10$ cm. How many such tiles are required to cover a floor of area $1080 m^{2}$ ? (If required you can split the tiles in whatever way you want to fill up the corners).