A flooring tile has the shape of a parallelogram whose base is $24 c m$ and the corresponding height is $10 c m$ . How many such tiles are required to cover a floor of area $1080 m^{2}$ ?

45, 000

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75, 000

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40, 000

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45, 00

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Solution

The correct option is A $45, 000$
Area of one tile $= b a s e \times h e i g h t$

$= (24 \times 10) c m^{2}$

$= 240 c m^{2}$ .

Number of tiles required to cover the floor $= \frac{A r e a o f t h e f l o o r}{A r e a o f o n e t i l e}$

$= \frac{1080 \times 100 \times 100}{240} [∵ 1 m^{2} = 100 \times 100 c m^{2}]$

$= 45, 000$ .

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A flooring tile has the shape of a parallelogram whose base is $24 c m$ and the corresponding height is $10 c m .$ How many such tiles are required to cover a floor of area $1080 m^{2}$

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A flooring tile has the shape of a parallelogram whose base is 24cm and the corresponding height is 10cm. How many such tiles are required to cover a floor of area 1080m2 ?

The correct option is A 45,000Area of one tile =base×height=(24×10)cm2=240cm2.Number of tiles required to cover the floor =AreaofthefloorAreaofonetile=1080×100×100240[∵1m2=100×100cm2]=45,000.

A flooring tile has the shape of a parallelogram whose base is $24 c m$ and the corresponding height is $10 c m$ . How many such tiles are required to cover a floor of area $1080 m^{2}$ ?