Question

A flooring tile has the shape of a parallelogram whose base is $24cm$ and the corresponding height is $10cm.$ How many such tiles are required to cover a floor of area $1080m^2$

Answer 1

Given : Base of the given parallelogram $=24cm$

Height of the given parallelogram $=20cm$

Area of floor $=1080m^2=1080\times 100\times 100c{m}^2$

$[1m^2=10000c{m}^2]$

Area of the Parallelogram $=base\times height$

$=24\times 10=240c{m}^2$

Area of $1$ tile $=240c{m}^2$

[Tiles are in the shape of a parallelogram]

Number of tiles required $=\frac{\text{Area of the Floor}}{\text{Area of the Tiles}}$

$=\frac{1080\times 100\times 100}{240}=45000$

Number of tiles required to cover a Floor of area $1080m^2=45000$