A flooring tile is in the shape of a parallelogram of base is 24 cm and height is 10 cm. The number of such tiles required to cover a floor of area 1080 $m^{2}$ is___ .

34000

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44000

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45000

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54000

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Solution

The correct option is C
45000

Area of parallelogram = Base $\times$ Height $= 24 c m \times 10 c m = 240 s q . c m$ .

Required number of tiles

$= \frac{A r e a o f f l o o r}{A r e a o f 1 t i l e} = \frac{1080 \times 100 \times 100}{240}$ (converting sq. m to sq. cm)

$= 45000 t i l e s$

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A flooring tile is in the shape of a parallelogram of base is 24 cm and height is 10 cm. The number of such tiles required to cover a floor of area 1080 m2 is___ .

The correct option is C 45000 Area of parallelogram = Base × Height =24 cm×10 cm=240 sq.cm. Required number of tiles =Area of floorArea of 1 tile=1080×100×100240 (converting sq. m to sq. cm) =45000 tiles

A flooring tile is in the shape of a parallelogram of base is 24 cm and height is 10 cm. The number of such tiles required to cover a floor of area 1080 $m^{2}$ is___ .

The correct option is C
45000

Area of parallelogram = Base $\times$ Height $= 24 c m \times 10 c m = 240 s q . c m$ .

Required number of tiles

$= \frac{A r e a o f f l o o r}{A r e a o f 1 t i l e} = \frac{1080 \times 100 \times 100}{240}$ (converting sq. m to sq. cm)

$= 45000 t i l e s$