Question

A flowerpot falls from a windowsill $25.0m$ above the sidewalk. How much time does a passerby on the sidewalk below have to move out of the way before the flowerpot hits the ground? (in seconds)

• A. $2$
  
• B. $2.3$
  
• C. $6$
  
• D. $9$
  

Answer 1

Answer: (B)

$2.3$

Initial speed of flowerpot $u=0$
Height from which it was dropped $S=25.0m$
Applying $2_{nd}$ eqn of motion,
$S=ut+\frac{1}{2}a{t}^2$
$25=0\times t+\frac{1}{2}\times 9.8\times t^2$
$⟹t=2.3s$