A football of mass $0.5 k g$ moving with a velocity of $10 m s^{- 1}$ hits a pole and, the ball turns back and moves with a velocity of $20 m s^{- 1}$ . Find the impulse and the force exerted on the ball if the force acts for $0.02 s$ .

Open in App

Solution

Impulse $= m Δ v = 0.5 (10 - (- 20)) = 15 k g . m / s$
Force $= \frac{I m p u l s e}{t i m e} = \frac{15}{0.02} = 750 N$ .

Suggest Corrections

Similar questions

Q. A cricket ball of mass 120 g is moving with a velocity of

12 m s^{- 1}

, it turns back and move with a velocity of

20 m s^{- 1}

when hit by a bat. Find the impulse and the force, if the force acts for 0.02 s.

A football of mass 5 kg moving with a velocity of 10 m/s hits a pole and, the ball bounces back with a velocity of 5m/s. Find the change in momentum and the force exerted on the ball, if the force acts for 0.02s.

Q. A cricket ball of mass 120 g is moving with a velocity of 12 m

s^{- 1}

. It turns back and moves with a velocity of 20 m

s^{- 1}

when hit by a bat. Find the impulse if the force acts on the ball for 0.02 s.

A cricket ball of mass $150 g$ is moving with a velocity $12 m s^{- 1}$ and is hit by a bat so that the ball is turned back with a velocity of $20 m s^{- 1}$ . If the duration of contact between the ball and bat is $0.01 s$ , find the impulse and the average force exerted on the ball by the bat.

A cricket ball of mass 150 gm is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01s on the ball. The average force exerted by the bat on the ball is

Join BYJU'S Learning Program

A football of mass 0.5 kg moving with a velocity of 10 ms−1 hits a pole and, the ball turns back and moves with a velocity of 20 ms−1. Find the impulse and the force exerted on the ball if the force acts for 0.02 s.

Impulse =mΔv=0.5(10−(−20))=15kg.m/sForce =Impulsetime=150.02=750N.

A football of mass $0.5 k g$ moving with a velocity of $10 m s^{- 1}$ hits a pole and, the ball turns back and moves with a velocity of $20 m s^{- 1}$ . Find the impulse and the force exerted on the ball if the force acts for $0.02 s$ .

Impulse $= m Δ v = 0.5 (10 - (- 20)) = 15 k g . m / s$
Force $= \frac{I m p u l s e}{t i m e} = \frac{15}{0.02} = 750 N$ .