A force $(2^i +^j -^k) N$ acts on a body which is initially at rest. At the end of $20 s$ the velocity of the body is $(4^i + 2^j - 2^k) m s^{- 1}$ , then the mass of the body is:

8 k g

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10 k g

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5 k g

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4.5 k g

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Solution

The correct option is D $10 k g$

$F = \sqrt{4 + 1 + 1} = \sqrt{6}$

$V = \sqrt{16 + 4 + 4} = \sqrt{24}$

$F = m (\frac{v - u}{t})$

$\sqrt{6} = m (\frac{\sqrt{24} - 0}{20})$
$m = \frac{\sqrt{6} \times 20}{\sqrt{24}} = \frac{20}{2} = 10$

$m = 10 k g$

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