A force (3^i+2^j)N displaces an object through a distance (2^i−3^j)m. The work done is :
A
Zero
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B
12 J
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C
5 J
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D
13 J
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Solution
The correct option is D Zero Given →F=3→i+2→j →r=2→i−3→j The work done on the particle is a scalar product of F and r, hence W=F.r W=(3→i+2→j).(2→i−3→j) W=6−6=0J