A force (4^i+^j−2^k)N acting on a body maintains its velocity at (2^i+3^j−^k)m/s. The power exerted is
A
15W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
13W
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B13W We have force →F=(4^i+^j−2^k)N
Velocity,→v=(2^i+3^j−^k)m/s
Therefore, Power is given by P=→F.→v=(4^i+^j−2^k).(2^i+3^j−^k) ⇒P=(8+3+2)W ⇒P=13W