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Question

# A uniform force of (3^i+^j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2^i+^k) m to position (4^i+3^j−^k) m. The work done by the force on the particle is -

A
15 J
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B
6 J
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C
13 J
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D
9 J
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Solution

## The correct option is D 9 JThe position vectors of initial and final position are, →ri=2^i+^k, →rf=4^i+3^j−^k The displacement vector is given by, →S=→rf−→ri ∴→S=2^i+3^j−2^k And, →F=3^i+^j The work done is given by, W=→F⋅→S =3×2+1×3+0×(−2)=9 J <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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