A uniform force of (3^i+^j) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2^i+^k) meter to position (4^i+3^j−^k) meter. The work done by the force on the particle is
A
9J
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B
6J
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C
13J
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D
15J
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Solution
The correct option is A9J →F=3^i+^j →S=→r2−→r1=2^i+3^j−2^k W=→F.→S=6+3+0=9J