A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m $s^{- 1}$ . Find the magnitude of force.

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Solution

We know that, $F = \frac{m v - m u}{t} \Rightarrow F = \frac{2 \times 2 - 2 \times 0}{0.1} = 40 N$

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A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m s−1. Find the magnitude of force.

We know that, F=mv−mut⇒F=2×2−2×00.1=40 N

A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m $s^{- 1}$ . Find the magnitude of force.

We know that, $F = \frac{m v - m u}{t} \Rightarrow F = \frac{2 \times 2 - 2 \times 0}{0.1} = 40 N$