Question

A force acts for 10 s on a body of mass 10 kg after which the force ceases and the body travels 50 m in the next 5 s. Find the magnitude of the force.

• A. 5 N
• B. 10 N
• C. 15 N
• D. 50 N

Answer 1

The correct option is B 10 N

initial velocity is 0

then, $v=u+at$

$v=0+a10$

$v=10a$

After 10s body starts moving and covers 50m in 5s

$S=vt$

$50=\left(10a\right)5$

$a=1m/s^2$

using the value of a in $F=ma$

$F=10\times 1=10N$